TS EAMCET · Maths · Vector Algebra
The shortest distance between the skew lines \(\hat{\mathbf{r}}=(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+3 \hat{\mathbf{k}})+t(\hat{\mathbf{i}}+3 \hat{\mathbf{j}}+2 \hat{\mathbf{k}})\) and \(\hat{\mathbf{r}}=(4 \hat{\mathbf{i}}+5 \hat{\mathbf{j}}+6 \hat{\mathbf{k}})+t(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+\hat{\mathbf{k}})\) is
- A \(sqrt{6}\)
- B \(3\)
- C \(2 \sqrt{3}\)
- D \(sqrt{3}\)
Answer & Solution
Correct Answer
(D) \(sqrt{3}\)
Step-by-step Solution
Detailed explanation
Given skew lines are \(\mathbf{r}=(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+3 \hat{\mathbf{k}})+t(\hat{\mathbf{i}}+3 \hat{\mathbf{j}}+2 \hat{\mathbf{k}})\) and…
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