TS EAMCET · Maths · Trigonometric Ratios & Identities
\(\operatorname{cosec} 15^{\circ}+\sec 15^{\circ}\) is equal to :
- A \(2 \sqrt{2}\)
- B \(\sqrt{6}\)
- C \(2 \sqrt{6}\)
- D \(\sqrt{6}+\sqrt{2}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{6}+\sqrt{2}\)
Step-by-step Solution
Detailed explanation
\(\operatorname{cosec} 15^{\circ}+\sec 15^{\circ}\) \(=\frac{2\left(\sin 15^{\circ}+\cos 15^{\circ}\right)}{2 \sin 15^{\circ} \cos 15^{\circ}}\)…
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