TS EAMCET · Maths · Vector Algebra
If \(\bar{a}\) and \(\bar{b}\) are two vectors such that \(|\bar{a}|=5,|\bar{b}|=12\) and \(|\bar{a}-\bar{b}|=13\) then \(|2 \bar{a}+\bar{b}|=\)
- A \(2 \sqrt{61}\)
- B \(15\)
- C \(61 \sqrt{2}\)
- D \(17\)
Answer & Solution
Correct Answer
(A) \(2 \sqrt{61}\)
Step-by-step Solution
Detailed explanation
\(|\bar{a}-\bar{b}|^2 = |\bar{a}|^2 + |\bar{b}|^2 - 2(\bar{a} \cdot \bar{b})\) \(13^2 = 5^2 + 12^2 - 2(\bar{a} \cdot \bar{b})\) \(169 = 25 + 144 - 2(\bar{a} \cdot \bar{b})\) \(2(\bar{a} \cdot \bar{b}) = 169 - 169 = 0 \implies \bar{a} \cdot \bar{b} = 0\)…
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