TS EAMCET · Maths · Three Dimensional Geometry
The radius of the sphere \(x^2+y^2+z^2=12 x+4 y+3 z\) is
- A \(\frac{13}{2}\)
- B 13
- C 26
- D 52
Answer & Solution
Correct Answer
(A) \(\frac{13}{2}\)
Step-by-step Solution
Detailed explanation
Given equation of sphere is \(x^2+y^2+z^2-12 x-4 y-3 z=0\) \(\therefore \quad\) Centre of sphere is \(\left(6,2, \frac{3}{2}\right)\).…
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