TS EAMCET · Maths · Quadratic Equation
If the roots \(\alpha, \beta, \gamma\) of the equation \(x^3-6 x^2+p x+10=0\) are in arithmetic progression, then \(\alpha^3+\beta^3+\gamma^3=\)
- A 132
- B 134
- C 629
- D 645
Answer & Solution
Correct Answer
(A) 132
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\(\alpha, \beta, \gamma\) are roots of equation…
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