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TS EAMCET · Maths · Circle

The radius of a circle touching all the four circles \((x \pm \lambda)^2+(y \pm \lambda)^2=\lambda^2\) is

  1. A \(2 \sqrt{2} \lambda\)
  2. B \((\sqrt{2}-1) \lambda\)
  3. C \((2+\sqrt{2}) \lambda\)
  4. D \((2-\sqrt{2}) \lambda\)
Verified Solution

Answer & Solution

Correct Answer

(B) \((\sqrt{2}-1) \lambda\)

Step-by-step Solution

Detailed explanation

Clearly the required circle have circle with centre at origin In figure, If radius of such circle \(=r\) then \(\mathrm{OB}=r\)…
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