TS EAMCET · Maths · Parabola
The parametric equations of the parabola are
- A
- B
- C
- D
Answer & Solution
Correct Answer
(D)
Step-by-step Solution
Detailed explanation
y2-4x-8y-12=0 y2-8y=4x+12 y2-8y+16-16=4x+12 y-42=4x+28 y-42=4x+7 Let y-4=Y,x+7=X ⇒Y2=4X On comparing it with y2=4ax, we get 4a=4 a=1 Parametric equations are X=at2,Y=2at x+7=t2 & y-4=2t
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- Consider the lines If the line intersects the lines and at the points and respectively, then the combined equation of and isTS EAMCET 2021 Medium
- If the position vectors of the points \(A, B, C, D\) given by \(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}, 2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+2 \hat{\mathbf{k}}\), \(\frac{1}{4}(7 \hat{\mathbf{i}}+15 \hat{\mathbf{j}}+15 \hat{\mathbf{k}}) \text { and } \frac{1}{3}[7 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}+(5+3 a) \hat{\mathbf{k}}]\) respectively are such that \(|\mathbf{A C}|=|\mathbf{B D}|\), then \(16(3 a-1)^2=\)TS EAMCET 2019 Medium
- If \(2 \vec{i}-\hat{j}+3 \hat{k},-12 \hat{i}-\hat{j}-3 \hat{k},-\hat{i}+2 \hat{j}-4 \hat{k}\) and \(\lambda \hat{i}+2 \hat{j}-\hat{k}\) are the position vectors of four coplanar points, then \(\lambda=\)TS EAMCET 2023 Easy
- If \(\frac{42-13 x}{x^2+x-6}=\frac{\mathrm{A}}{l x+m}+\frac{\mathrm{B}}{p x+q}\) where \(l m>0\) and \(p q < 0\) then \(\frac{\mathrm{A} l p}{\mathrm{~B} m q}=\)TS EAMCET 2022 Medium
- The period of the function \(f(x)=e^{\log (\sin x)}+(\tan x)^3-\operatorname{cosec}(3 x-5)\) isTS EAMCET 2023 Easy
- A random variate \(X\) takes the values \(0,1,2,3\) and its mean is 1.3. If \(P(X=3)=2 P(X=1)\) and \(P(X=2)=0.3\), then \(P(X=0)\) is equal to :TS EAMCET 2003 Easy
More PYQs from TS EAMCET
- If a random variable \(\mathrm{X}\) follows a poisson distribution such that \(P(X=1)=3 P(X=2)\), then \(P(x=3)=\)TS EAMCET 2018 Medium
- Assertion : Tertiary alcohols produce turbidity immediately with Lucas reagent. Reason : Lucas reagent is a \(1: 1\) mixture of conc. \(\mathrm{HNO}_3\) and anhydrous \(\mathrm{ZnCl}_2\). The correct option among the following isTS EAMCET 2022 Easy
- For the equation \(x^4+x^3-4 x^2+x-1=0\) the ratio of the sum of the squares of all the roots to the product of the distinct roots isTS EAMCET 2020 Medium
- A bomb moving with velocity \((40 \hat{\mathbf{i}}+50 \hat{\mathbf{j}}-25 \hat{\mathbf{k}}) \mathrm{m} / \mathrm{s}\) explodes into two pieces of mass ratio \(1: 4\). After explosion the smaller piece moves away with velocity \((200 \hat{\mathbf{i}}+70 \hat{\mathbf{j}}+15 \hat{\mathbf{k}}) \mathrm{m} / \mathrm{s}\). The velocity of larger piece after explosion isTS EAMCET 2010 Medium
- A crystal of intrinsic silicon at room temperature has a carrier concentration of \(1.6 \times 10^{16} / \mathrm{m}^3\). If the donor concentration level is \(4.8 \times 10^{20} / \mathrm{m}^3\), then the concentration of holes in the semiconductor isTS EAMCET 2014 Easy
- Dispersive power depends on the following :TS EAMCET 2006 Easy