TS EAMCET · Maths · Straight Lines
The orthocenter of the triangle whose sides are given by \(x+y+10=0, x-y-2=0\) and \(2 x+y-7=0\) is
- A \((-4,-3)\)
- B \((-4,-6)\)
- C \((4,6)\)
- D \((3,6)\)
Answer & Solution
Correct Answer
(B) \((-4,-6)\)
Step-by-step Solution
Detailed explanation
\(\mathrm{L}_1: x+y+10=0 ; \mathrm{L}_2: x-y-2=0\) \(\begin{aligned} & \mathrm{L}_3: 2 x+y-7=0 \\ & \because \mathrm{L}_1 \perp \mathrm{L}_2 \\ & \therefore \text { orthocentre will be point of intersection of } \mathrm{L}_1 \& \mathrm{~L}_2\end{aligned}\) \(x+y+10=0\)...(i)…
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