TS EAMCET · Maths · Complex Number
If \(x=p+q, y=p \omega+q \omega^2 \quad\) and \(\quad z=p \omega^2+q \omega\), where \(\omega\) is a complex cube root of unity, then \(x y z\) equals to
- A \(p^3+q^3\)
- B \(p^2-p q+q^3\)
- C \(1+p^3+q^3\)
- D \(p^3-q^3\)
Answer & Solution
Correct Answer
(A) \(p^3+q^3\)
Step-by-step Solution
Detailed explanation
Given, \(\quad x=p+q, \quad y+p \omega+q \omega^2 \quad\) and \(z=p \omega^2+q \omega\)…
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