TS EAMCET · Maths · Hyperbola
Let \(A(2 \sec \theta, 3 \tan \theta)\) and \(B(2 \sec \phi, 3 \tan \phi)\) where \(\theta+\phi=\frac{\pi}{2}\), be two points on the hyperbola \(\frac{x^2}{4}-\frac{y^2}{9}=1\). If \((\alpha, \beta)\) is the point of intersection of normals to the hyperbola at \(A\) and \(B\), then \(\beta\) is equal to
- A \(-\frac{13}{3}\)
- B \(\frac{13}{3}\)
- C \(\frac{3}{13}\)
- D \(-\frac{3}{13}\)
Answer & Solution
Correct Answer
(A) \(-\frac{13}{3}\)
Step-by-step Solution
Detailed explanation
The normal at point \(A(2 \sec \theta, 3 \tan \theta)\) is \[ \begin{aligned} 2 x \cos \theta+3 y \cot \theta=4+9 \\ 2 x \cos \theta+3 y \cot \theta=13 \end{aligned} \] And the normal at point \(B(2 \sec \phi, 3 \tan \phi)\) is…
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