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TS EAMCET · Maths · Permutation Combination

The number of integers \(x, y, z, w\) satisfying \(x+y+z+w=25\) and \(x, y, z \geq-1, w \geq 1\), is

  1. A \({ }^{28} C_3\)
  2. B \({ }^{30} C_3\)
  3. C \({ }^{29} \mathrm{C}_3\)
  4. D \({ }^{31} C_3\)
Verified Solution

Answer & Solution

Correct Answer

(B) \({ }^{30} C_3\)

Step-by-step Solution

Detailed explanation

It is given that, \(x, y, z \geq-1\) and \(w \geq 1\) Now, let \(a=x+1 \geq 0\) \(b=y+1 \geq 0\) \(c=z+1 \geq 0\) \(d=w-1 \geq 0\) \(\therefore\) The given equation \(x+y+z+w=25\) reduce to \((a-1)+(b-1)+(c-1)+(d+1)=25\) \(\Rightarrow \quad a+b+c+d=27\) \(\therefore\) The number…