TS EAMCET · Maths · Complex Number
If \(\alpha, \beta\) are the roots of \(1+x+x^2=0\), then the value of \(\alpha^4+\beta^4+\alpha^{-4} \beta^{-4}\) is
- A 0
- B 1
- C -1
- D 2
Answer & Solution
Correct Answer
(A) 0
Step-by-step Solution
Detailed explanation
We have, \[ \begin{aligned} 1+x+x^2 & =0 \\ \Rightarrow \quad x & =\frac{-1 \pm \sqrt{1-4}}{2} \Rightarrow x=\frac{-1 \pm \sqrt{3} i}{2} \\ \Rightarrow \quad x & =\omega, \omega^2 \end{aligned} \] It is given that, \(\alpha, \beta\) are the roots of the equation \(1+x+x^2=0\).…
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