TS EAMCET · Maths · Binomial Theorem
The middle term in the expansion of \(\left(4 x^3-\frac{15}{4 x}\right)^8\) is
- A \(70(15 x)^4\)
- B \(1820 x^8\)
- C \(70\left(15 x^2\right)^4\)
- D \(2560 x^4\)
Answer & Solution
Correct Answer
(C) \(70\left(15 x^2\right)^4\)
Step-by-step Solution
Detailed explanation
Here, \(n=8\) (even) \(\therefore\left(\frac{n}{2}+1\right)\) th term will be middle term. So,…
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