TS EAMCET · Maths · Complex Number
For \(n>1\) and \(n \in \mathbf{N}\), if \(z_1, z_2, \ldots, z_n\) are the roots of the equation \((z+1)^n=z^n\), then \(\sum_{i=1}^n \frac{\cot ^{-1}\left(2\left|\operatorname{Im} z_i\right|\right)-1}{2 \operatorname{Re} z_i}=\)
- A 0
- B i
- C \(\frac{1}{2}[\pi-(\pi-2) n]\)
- D \(\frac{1}{2}[\pi+(\pi+2) n]\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2}[\pi-(\pi-2) n]\)
Step-by-step Solution
Detailed explanation
Given, \(z_1, z_2, z_3, \ldots, z_n\) are roots of equation…
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