TS EAMCET · Maths · Vector Algebra
Vectors \(\vec{p}=a \hat{i}+b \hat{j}+c \hat{k}, \vec{q}=d \hat{i}+3 \hat{j}+4 \hat{k}\) and \(\vec{r}=3 \hat{i}+\hat{j}-2 \hat{k}\) forming a triangle \(\mathrm{ABC}\) are such that \(\vec{p}=\vec{q}+\vec{r}\). If the area of \(\triangle \mathrm{ABC}\) is \(5 \sqrt{6}\) sq. units, then the sum of the absolute values of \(a, b, c\) is
- A \(14\)
- B \(13\)
- C \(12\)
- D \(10\)
Answer & Solution
Correct Answer
(A) \(14\)
Step-by-step Solution
Detailed explanation
\(a \hat{i}+b \hat{j}+c \hat{k}=d \hat{i}+3 \hat{j}+4 \hat{k}+3 \hat{i}+\hat{j}-2 \hat{k}\) \(\begin{aligned} & a \hat{i}+b \hat{j}+c \hat{k}=(d+3) \hat{i}+4 \hat{j}+2 \hat{k} \\ & \therefore \quad a=d+3 \Rightarrow d=a-3 \\ & \quad b=4 \\ & \quad c=2\end{aligned}\) Area of…
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