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TS EAMCET · Maths · Application of Derivatives

If the area of a circle increases at the rate of \(\frac{1}{\sqrt{\pi}}\) sq. units/sec, then the rate (in units/sec) at which the perimeter of the circle changes, when perimeter is \(\sqrt{\pi}\) units, is

  1. A 2
  2. B 4
  3. C \(\frac{1}{\sqrt{\pi}}\)
  4. D \(\sqrt{\pi}\)
Verified Solution

Answer & Solution

Correct Answer

(A) 2

Step-by-step Solution

Detailed explanation

Let \(A\) and \(P\) are area and perimeter of circle. We have, \(\frac{d A}{d t}=\frac{1}{\sqrt{\pi}} \Rightarrow \frac{d}{d t}\left(\pi r^2\right)=\frac{1}{\sqrt{\pi}}\)…