TS EAMCET · Maths · Straight Lines
If a straight line \(L\) passing through the point \((5,-3)\) is inclined at an angle of \(60^{\circ}\) to the line \(\sqrt{3} x+y-9=0\) and \(\mathrm{L}\) intersects \(\mathrm{X}\)-axis then the equation of \(\mathrm{L}\) is
- A \(x-\sqrt{3} y-3-5 \sqrt{3}=0\)
- B \(\sqrt{3} x-y-3-5 \sqrt{3}=0\)
- C \(\sqrt{3} x-y+3+5 \sqrt{3}=0\)
- D \(x-\sqrt{3} y+3+5 \sqrt{3}=0\)
Answer & Solution
Correct Answer
(B) \(\sqrt{3} x-y-3-5 \sqrt{3}=0\)
Step-by-step Solution
Detailed explanation
Let \(L_1=\sqrt{3} x+y-9=0 \Rightarrow m_1=-\sqrt{3}\) \[ \mathrm{L}_2=\mathrm{ax}+\mathrm{by}+\mathrm{c}=0 \Rightarrow \mathrm{m}_2=-\mathrm{a} / \mathrm{b} \] given, angle between \(\mathrm{L}_1\) and \(\mathrm{L}_2\) is \(60^{\circ}\)…
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