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TS EAMCET · Maths · Trigonometric Equations

The equation sin4x-k+3sin2x-k-4=0 has a solution if

  1. A k>4
  2. B -4k-3
  3. C k is any positive integer
  4. D k=0
Verified Solution

Answer & Solution

Correct Answer

(B) -4k-3

Step-by-step Solution

Detailed explanation

Given: The equation sin4x-k+3sin2x-k-4=0 has a solution It is a quadratic equation in sin2x So, sin2x=k+3±k+32+4k+42 =k+3±k+522 =k+3±k+52=k+4, -2 but sin2x∈0,1 ⇒0≤k+4≤1⇒-4≤k≤-3.
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