TS EAMCET · Maths · Straight Lines
The equation of the straight line perpendicular to the straight line \(3 x+2 y=0\) and passing through the point of intersection of the lines \(x+3 y-1=0\) and \(x-2 y+4=0\) is
- A \(2 x-3 y+1=0\)
- B \(2 x-3 y+3=0\)
- C \(2 x-3 y+5=0\)
- D \(2 x-3 y+7=0\)
Answer & Solution
Correct Answer
(D) \(2 x-3 y+7=0\)
Step-by-step Solution
Detailed explanation
The point of intersection of lines \(x+3 y-1=0\) and \(x-2 y+4=0\) is \((-2,1)\). Let equation of line perpendicular to the given line is \(2 x-3 y+\lambda=0\). Since, it passes through \((-2,1)\).…
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