TS EAMCET · Maths · Statistics
If the coefficients of variation of two distributions are 40 and 20 and their variances are 144 and 64 respectively, then the mean of their arithmetic means is (a) 40 (b) 12 (c) 30 (d) 35
- A 40
- B 12
- C 30
- D 35
Answer & Solution
Correct Answer
(D) 35
Step-by-step Solution
Detailed explanation
Let \(\bar{x}_1, \bar{x}_2\) be the means and \(\sigma_1^2, \sigma_2^2\) be the variances of two distributions. Then, we have, \(\sigma_1^2=144, \sigma_2^2=64\), \[ \frac{\sigma_1}{\bar{x}_1} \times 100=40 \text { and } \frac{\sigma_2}{\bar{x}_2} \times 100=20 \] Now,…
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