TS EAMCET · Maths · Circle
The equation of the radical axis of the pair of circles \(7 x^2+7 y^2-7 x+14 y+18=0\) and \(4 x^2+4 y^2-7 x+8 y+20=0\) is
- A \(x-2 y-5=0\)
- B \(2 x-y+5=0\)
- C \(21 x-68=0\)
- D \(23 x-68=0\)
Answer & Solution
Correct Answer
(C) \(21 x-68=0\)
Step-by-step Solution
Detailed explanation
Let \(S_1 \equiv x^2+y^2-x+2 y+\frac{18}{7}=0\) and \(S_2 \equiv x^2+y^2-\frac{7}{4} x+2 y+5=0\) Now, the radical axis of the pair of circles are \(S_1-S_2=0\) \(\Rightarrow \quad\left(x^2+y^2-x+2 y+\frac{18}{7}\right)\) \(-\left(x^2+y^2-\frac{7}{4} x+2 y+5\right)=0\)…
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