TS EAMCET · Maths · Properties of Triangles
Let one of the sides of a triangle be \(17 \mathrm{~cm}\) and the sum of all the sides of the triangle be \(40 \mathrm{~cm}\). If the sum of two adjacent sides is \(35 \mathrm{~cm}\), then the area (in sq. cms) of the triangle is
- A \(15 \sqrt{2}\)
- B \(20 \sqrt{2}\)
- C \(30 \sqrt{2}\)
- D \(35 \sqrt{2}\)
Answer & Solution
Correct Answer
(C) \(30 \sqrt{2}\)
Step-by-step Solution
Detailed explanation
According to given informations, Let \(a=17, a+b+c=40\) and \(a+b=35\) So, \(b=18\) and \(c=5\) \(\because\) Area of required triangle is \(\sqrt{s(s-a)(s-b)(s-c)}\) \(\left[\right.\) where, \(\left.s=\frac{a+b+c}{2}=20\right]\) \(=\sqrt{20(3)(2)(15)}=30 \sqrt{2}\) Hence, option…
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