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TS EAMCET · Maths · Circle

The equation of the circle touching the line \(2 x+3 y+1=0\) at the point \((1,-1)\) and orthogonal to the circle which has the line segment having end points \((0,-1)\) and \((-2,3)\) as diameter, is

  1. A \(x^2+y^2-10 x+5 y+1=0\)
  2. B \(x^2+y^2+5 x-10 y-1=0\)
  3. C \(2 x^2+2 y^2+10 x-5 y-1=0\)
  4. D \(2 x^2+2 y^2-10 x-5 y+1=0\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2 x^2+2 y^2-10 x-5 y+1=0\)

Step-by-step Solution

Detailed explanation

Let the equation of circle is \( x^2+y^2+2 g x+2 f y+c=0 \) It is passes through \((1,-1)\) \( \therefore \quad 2 g-2 f+c=-2 \) Equation of circle whose end point of diametre \((0,-1)\) and \((-2,3)\) is…
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