TS EAMCET · Maths · Vector Algebra
Let \(\mathbf{a}=2 \hat{\mathbf{i}}-2 \hat{\mathbf{j}}+\hat{\mathbf{k}}, \mathbf{b}=-\hat{\mathbf{j}}+\hat{\mathbf{k}}\). If \(\mathbf{c}\) is a vector such that \(\mathbf{a} \cdot \mathbf{c}=|\mathbf{c}|,|\mathbf{c}-\mathbf{a}|=2 \sqrt{2}\) and the angle between \(\mathbf{a} \times \mathbf{b}\) and \(\mathbf{c}\) is \(\frac{\pi}{3}\), then \(|(\mathbf{a} \times \mathbf{b}) \times \mathbf{c}|=\)
- A \(3 \sqrt{3}\)
- B \(\frac{3}{2}\)
- C \(\frac{3 \sqrt{3}}{2}\)
- D 0
Answer & Solution
Correct Answer
(C) \(\frac{3 \sqrt{3}}{2}\)
Step-by-step Solution
Detailed explanation
Given, \(\mathbf{a}=2 \hat{\mathbf{i}}-2 \hat{\mathbf{j}}+\hat{\mathbf{k}}\), then \(|\mathbf{a}|=\sqrt{4+4+1}=3\) Now given \(|\mathbf{c}-\mathbf{a}|=2 \sqrt{2}\) Squaring on both sides,…
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