TS EAMCET · Maths · Circle
The equation of the circle passing through the origin and cutting the circles \(x^2+y^2+6 x-15=0\) and \(x^2+y^2-8 y-10=0\) orthogonally is
- A \(2 x^2+2 y^2-5 x+10 y=0\)
- B \(2 x^2+2 y^2-10 x+5 y=0\)
- C \(x^2+y^2-2 x+5 y=0\)
- D \(x^2+y^2-5 x+2 y=0\)
Answer & Solution
Correct Answer
(B) \(2 x^2+2 y^2-10 x+5 y=0\)
Step-by-step Solution
Detailed explanation
\(S \equiv x^2+y^2+2 g x+2 f y=0\) is a circle passing through \((0,0)\) \(\begin{aligned} & S_1 \equiv x^2+y^2+6 x-15=0 \\ & S_2 \equiv x^2+y^2-8 y-10=0\end{aligned}\) \(S\) cuts \(S_1\) and \(S_2\) orthogonally…
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