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TS EAMCET · Maths · Continuity and Differentiability

If \(f(x)=\left\{\begin{array}{cc}\frac{\sqrt{1+p x}-\sqrt{1-p x}}{x}, & -1 \leq x < 0 \ \frac{2 x+1}{x-2}, & 0 \leq x \leq 1\end{array}\right.\) is continuous on \([-1,1]\), then \(p=\)

  1. A \(-\frac{1}{2}\)
  2. B \(-\frac{1}{4}\)
  3. C \(\frac{1}{2}\)
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(A) \(-\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

\(f(x)=\left\{\begin{array}{c}\frac{\sqrt{1+p x}-\sqrt{1-p x}}{x},-1 \leq x < 0 \\ \frac{2 x+1}{x-2}, 0 \leq x \leq 1\end{array}\right.\) Continues in \([-1,1]\), so it is continues at \(x=0\) also So,…