TS EAMCET · Maths · Determinants
If \(a \neq b \neq c, \Delta_1=\left|\begin{array}{lll}1 & a^2 & b c \\ 1 & b^2 & c a \\ 1 & c^2 & a b\end{array}\right|, \Delta_2=\left|\begin{array}{ccc}1 & 1 & 1 \\ a^2 & b^2 & c^2 \\ a^3 & b^3 & c^3\end{array}\right|\) and \(\frac{\Delta_1}{\Delta_2}=\frac{6}{11}\), then \(11(a+b+c)=\)
- A 0
- B 1
- C \(a b+b c+c a\)
- D \(6(a b+b c+c a)\)
Answer & Solution
Correct Answer
(D) \(6(a b+b c+c a)\)
Step-by-step Solution
Detailed explanation
\(\Delta_1=\left|\begin{array}{ccc}1 & a^2 & b c \\ 1 & b^2 & c a \\ 1 & c^2 & a b\end{array}\right|\) \(\text {Applying } R_2 \rightarrow R_2-R_1 ; R_3 \rightarrow R_3-R_1\)…
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