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TS EAMCET · Maths · Definite Integration

If 02ax22ax-x2dx=ka4, then k:π=

  1. A 1:8
  2. B 3:8
  3. C 5:8
  4. D 9:8
Verified Solution

Answer & Solution

Correct Answer

(C) 5:8

Step-by-step Solution

Detailed explanation

Given that, ∫02ax22ax-x2dx=ka4 Let, I=∫02ax22ax-x2dx Put, x=2asin2θ⇒dx=4asinθcosθdθ And, 2ax-x2=4a2sin2θcos2θ=2asinθcosθ. Therefore,…
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