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TS EAMCET · Maths · Trigonometric Ratios & Identities

If An=sinnα+cosnα, then A1A4+A2A5=

  1. A A1A2+A4A5
  2. B A1A6+A2A3
  3. C A1A3+A2A6
  4. D A1A2+A3A6
Verified Solution

Answer & Solution

Correct Answer

(B) A1A6+A2A3

Step-by-step Solution

Detailed explanation

Given that, An=sin4α+cos4α And A1A4+A2A5=sinα+cosαsin4α+cos4α+sin2α+cos2αsin5α+cos5α ⇒A1A4+A2A5=sinα+cosαsin4α+cos4α+sin5α+cos5α Consider,…