TS EAMCET · Maths · Straight Lines
If the line joining the points \(A(b \cos \alpha, b \sin \alpha)\) and \(B(a \cos \beta, a \sin \beta)\) is extended to the point \(N(x, y)\) such that \(A N: N B=b: a\), then
- A \(x \cos \frac{\alpha-\beta}{2}+y \sin \frac{\alpha+\beta}{2}=0\)
- B \(x \cos \frac{\alpha-\beta}{2}+y \sin \frac{\alpha-\beta}{2}=0\)
- C \(x \cos \frac{\alpha+\beta}{2}+y \sin \frac{\alpha+\beta}{2}=0\)
- D \(x \cos \frac{\alpha+\beta}{2}+y \sin \frac{\alpha-\beta}{2}=0\)
Answer & Solution
Correct Answer
(C) \(x \cos \frac{\alpha+\beta}{2}+y \sin \frac{\alpha+\beta}{2}=0\)
Step-by-step Solution
Detailed explanation
Coordinate of \(N\) will be \( x=\frac{m_1 x_2-m_2 x_1}{m_1-m_2}, \quad y=\frac{m_1 y_2-m_2 y_1}{m_1-m_2} \) So, \( x=\frac{b \cdot a \cos \beta-a \cdot b \cos \alpha}{b-a}, \) \(\Rightarrow \quad y=\frac{b \cdot a \sin \beta-a \cdot b \sin \alpha}{b-a}\)…
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