TS EAMCET · Maths · Probability
A random variable \(\mathrm{X}\) takes the values 0,1 and 2. If \(P(X=1)=P(X=2)\) and \(P(X=0)=0.4\), then the mean of the random variable \(\mathrm{X}\) is
- A \(0.2\)
- B \(0.7\)
- C \(0.5\)
- D \(0.9\)
Answer & Solution
Correct Answer
(D) \(0.9\)
Step-by-step Solution
Detailed explanation
We have, \(P(X=1)=P(X=2)\) \[ \frac{\lambda^1}{1 !} e^\lambda=\frac{\lambda^2}{2 !} e^\lambda \Rightarrow \lambda=2 \] Also, \(P(X=0)+P(X=1)+P(X=2)=1\)…
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