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TS EAMCET · Maths · Parabola

The equation of the common tangent of the parabolas \(x^2=108 y\) and \(y^2=32 x\) is

  1. A \(2 x+3 y+36=0\)
  2. B \(2 x+3 y=36\)
  3. C \(3 x+2 y+36=0\)
  4. D \(3 x+2 y=36\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2 x+3 y+36=0\)

Step-by-step Solution

Detailed explanation

(a) Given equation of parabola \(x^2=108 y(4 a=108 \Rightarrow a=27)\) Equation of tangent, \(y=m x-27 m^2\) \(\ldots(\mathrm{i})\) And equation of parabola \(y^2=32 x(4 a=32 \Rightarrow a=8)\) Equation of tangent, \(y=m x+\frac{8}{m}\) \(\ldots(\mathrm{ii})\) Since Eqs. (i) and…
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