TS EAMCET · Maths · Pair of Lines
The centroid of the triangle formed by the pair of straight lines \(12 x^2-20 x y+7 y^2=0\) and the line \(2 x-3 y+4=0\) is :
- A \(\left(-\frac{7}{3}, \frac{7}{3}\right)\)
- B \(\left(-\frac{8}{3}, \frac{8}{3}\right)\)
- C \(\left(\frac{8}{3}, \frac{8}{3}\right)\)
- D \(\left(\frac{4}{3}, \frac{4}{3}\right)\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{8}{3}, \frac{8}{3}\right)\)
Step-by-step Solution
Detailed explanation
The separate equation of pair of straight lines of \(12 x^2-20 x y+7 y^2=0\) are \((6 x-7 y)=0\) and \((2 x-y)=0\) These the equation of sides are \(6 x-7 y=0\) \(\ldots\) (i) \(2 x-y=0\) \(\ldots\) (ii) and \(2 x-3 y+4=0\) \(\ldots\) (iii) On solving these equations, taking two…
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