TS EAMCET · Maths · Circle
If the tangent drawn at the point \(P\) on the circle \(x^2+y^2\) \(+6 x+6 y=2\) meets the straight line \(5 x-2 y+6=0\) at a point \(\mathrm{Q}\) on the Y-axis, then the length of \(\mathrm{PQ}\) is
- A \(5\)
- B \(4\)
- C \(2\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
\(\because Q\) lies on \(y\)-axis \(\begin{aligned} & \therefore \quad x=0 \\ & \Rightarrow-2 y+6=0 \Rightarrow y=3 \end{aligned}\)…
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