TS EAMCET · Maths · Circle
The centre and radius of the circumcircle of the triangle formed by the lines \(2 x+3 y=10\), \(y=x\) and the \(X\)-axis are respectively.
- A \(\left(\frac{-5}{2}, \frac{3}{2}\right), \frac{\sqrt{34}}{2}\)
- B \(\left(\frac{5}{2}, 2\right), \frac{\sqrt{41}}{2}\)
- C \(\left(\frac{5}{2}, \frac{-1}{2}\right), \sqrt{\frac{13}{2}}\)
- D \(\left(\frac{1}{2}, \frac{-5}{2}\right), \sqrt{\frac{13}{2}}\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{5}{2}, \frac{-1}{2}\right), \sqrt{\frac{13}{2}}\)
Step-by-step Solution
Detailed explanation
We have, Equation of sides of triangle are \(2 x+3 y=10 \Rightarrow y=x \Rightarrow y=0\) Solving we get \(A(2,2), B(0,0), C(5,0)\) Let equation of circle formed by triangle is \(x^2+y^2+2 g x+2 f y+c=0\) put \((0,0) \Rightarrow c=0\) put \((5,0)\)…
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