TS EAMCET · Maths · Trigonometric Ratios & Identities
\(16 \sin 12^{\circ} \cos 18^{\circ} \sin 48^{\circ}=\)
- A \(\sqrt{10-2 \sqrt{5}}\)
- B \(\sqrt{10+2 \sqrt{5}}\)
- C \(\sqrt{5}-1\)
- D \(\sqrt{5}+1\)
Answer & Solution
Correct Answer
(A) \(\sqrt{10-2 \sqrt{5}}\)
Step-by-step Solution
Detailed explanation
\(16 \sin 12^{\circ} \cos 18^{\circ} \sin 48^{\circ} = 8 \sin 12^{\circ} (2 \sin 48^{\circ} \cos 18^{\circ})\) \( = 8 \sin 12^{\circ} (\sin(48^{\circ}+18^{\circ}) + \sin(48^{\circ}-18^{\circ})) = 8 \sin 12^{\circ} (\sin 66^{\circ} + \sin 30^{\circ})\)…
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