TS EAMCET · Maths · Binomial Theorem
If \(a_k\) is the coefficient of \(x^k\) in the expansion of \(\left(1+x+x^2\right)^n\) for \(k=0,1,2, \ldots, 2 n\), then \(a_1+2 a_2+3 a_3+\ldots+2 n a_{2 n}\) is equal to
- A \(-a_0\)
- B \(3^n\)
- C \(n \cdot 3^{n+1}\)
- D \(n \cdot 3^n\)
Answer & Solution
Correct Answer
(D) \(n \cdot 3^n\)
Step-by-step Solution
Detailed explanation
We have, \(\begin{aligned}\left(1+x+x^2\right)^n=a_0+a_1 x+a_2 x^2+a_3 x^3 & +\ldots \\ & +a_{2 \pi} x^{2 n}\end{aligned}\) On differentiating both sides, we get…
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