TS EAMCET · Maths · Area Under Curves
The area of the region bounded by the curves \(y=9 x^2\) and \(y=5 x^2+4\) (in sq units) is
- A 64
- B \(\frac{64}{3}\)
- C \(\frac{32}{3}\)
- D \(\frac{16}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{16}{3}\)
Step-by-step Solution
Detailed explanation
Intersecting point of \(y=9 x^2\) and \(y=5 x^2+4\) is given by \( \begin{aligned} & \Rightarrow \quad 4 x^2=4 \\ & \Rightarrow \quad x^2=1 \\ & \Rightarrow \quad x= \pm 1 \\ & \therefore \quad y=9( \pm 1)^2=9 \\ & \end{aligned} \) Hence, intersecting points are \(( \pm 1,9)\).…
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