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TS EAMCET · Maths · Basic of Mathematics

For all integers \(n \geq 1\), which of the following is divisible by 9 ?

  1. A \(8^n+1\)
  2. B \(4^n-3 n-1\)
  3. C \(3^{2 n}+3 n+1\)
  4. D \(10^n+1\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4^n-3 n-1\)

Step-by-step Solution

Detailed explanation

\(\because \quad 4^n=(1+3)^n\) \(=1+3 n+\frac{n(n-1)}{2 !} 3^2+\ldots\) \(\Rightarrow \quad 4^n-3 n-1=3^2\left[\frac{n(n-1)}{2 !}+\ldots\right]\) It is clear from above that \(4^n-3 n-1\) is divisible by 9 .