TS EAMCET · Maths · Pair of Lines
The area (in square unit) of the triangle formed by \(x+y+1=0\) and the pair of straight lines \(x^2-3 x y+2 y^2=0\) is
- A \(\frac{7}{12}\)
- B \(\frac{5}{12}\)
- C \(\frac{1}{12}\)
- D \(\frac{1}{6}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{12}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \text { Given, } & & x^2-2 x y-x y+2 y^2 & =0 \\ \Rightarrow & & (x-2 y)(x-y) & =0\end{aligned}\) \(\Rightarrow \quad x=2 y, \quad x=y\) ...(i) Also, \(x+y+1=0\) ...(ii) On solving Eqs. (i) and (ii), we get…
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