TS EAMCET · Maths · Area Under Curves
The area (in sq. units) of the portion lying above the \(X\)-axis and enclosed between the curves \(y^2=2 a x-x^2\) and \(y^2=a x\) is
- A \(a^2\left(\frac{-\pi}{2}+\frac{2}{3}\right)\)
- B \(a^2\left(\frac{2}{3}-\frac{\pi}{4}\right)\)
- C \(a^2\left(\frac{\pi}{4}-\frac{2}{3}\right)\)
- D \(a^2\left(\frac{\pi}{4}+\frac{2}{3}\right)\)
Answer & Solution
Correct Answer
(C) \(a^2\left(\frac{\pi}{4}-\frac{2}{3}\right)\)
Step-by-step Solution
Detailed explanation
Equation of given curves \(x^2+y^2-2 a x=0\) and \(y^2=a x\) \(\because\) Area of the portion lying above the \(X\)-axis and enclosed between the given curves, from the diagram is \(\int_0^a\left(\sqrt{2 a x-x^2}-\sqrt{a x}\right) d x\)…
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