TS EAMCET · Maths · Application of Derivatives
The angle between the curves \(x^2=8 y\) and \(x y=8\) is
- A \(\tan ^{-1}\left(\frac{-1}{3}\right)\)
- B \(\tan ^{-1}(-3)\)
- C \(\tan ^{-1}(-\sqrt{3})\)
- D \(\tan ^{-1}\left(\frac{-1}{\sqrt{3}}\right)\)
Answer & Solution
Correct Answer
(B) \(\tan ^{-1}(-3)\)
Step-by-step Solution
Detailed explanation
Given equation of curves are \[ \begin{aligned} & x^2=8 y \\ & x y=8 \end{aligned} \] On substituting the value of \(y\) from Eq. (i) in Eq. (ii), we get \[ \begin{aligned} x\left(\frac{x^2}{8}\right) & =8 \\ x^3 & =64 \\ x & =4 \end{aligned} \]…
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