TS EAMCET · Maths · Determinants
If \(a \neq p, b \neq q, c \neq r\) and \(\left|\begin{array}{ccc}p & b & c \\ p+a & q+b & 2 c \\ a & b & r\end{array}\right|=0\), then \(\frac{p}{p-a}+\frac{q}{q-b}+\frac{r}{r-c}\) is equal to :
- A 0
- B 1
- C 2
- D 3
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
We have, \(\left|\begin{array}{ccc}p & b & c \\ p+a & q+b & 2 c \\ a & b & r\end{array}\right|=0\) \(\Rightarrow \quad\left|\begin{array}{lll}p & b & c \\ p & b & c \\ a & b & r\end{array}\right|+\left|\begin{array}{lll}p & b & c \\ a & q & c \\ a & b & r\end{array}\right|=0\)…
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