TS EAMCET · Maths · Permutation Combination
Let \(x\) denote the number of ways of selecting at least one ball from a bag containing 3 identical red balls, 4 identical blue balls and 5 identical green balls. Let \(y\) denote the number of ways in which a student will fail in an examination, when he has to write the examination in 5 different subjects. Then \(x+y=\)
- A \(150\)
- B \(151\)
- C \(152\)
- D \(301\)
Answer & Solution
Correct Answer
(A) \(150\)
Step-by-step Solution
Detailed explanation
Number of ways to select at least one ball is \(\begin{aligned} x & =(3+1)(4+1)(5+1)-1 \\ & =4 \times 5 \times 6-1=119\end{aligned}\) and numbers of ways in which a student will fail in the examination is \(y=2^5-1=31\) \(\therefore \quad x+y=119+31=150\)
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