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TS EAMCET · Maths · Ellipse

If the straight line \(8 x+3 \sqrt{2} y=36\) touches the ellipse \(\frac{x^2}{9}+\frac{y^2}{4}=2\) at \((a, b)\), then \(a+\sqrt{2} b=\)

  1. A \(\frac{36}{5 \sqrt{2}}\)
  2. B \(\frac{8}{3}\)
  3. C \(\frac{12+2 \sqrt{2}}{3}\)
  4. D \(\frac{16}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{16}{3}\)

Step-by-step Solution

Detailed explanation

Given, \(8 x+3 \sqrt{2} y=36\) \( \frac{x^2}{9}+\frac{y^2}{4}=2,(a, b) \) \( \begin{gathered} \frac{x x_1}{9}+\frac{y y_1}{4}-2=0 \\ 8 x+3 \sqrt{2} y-36=0 \end{gathered} \) Eqs. (i) and (ii) represents same line, so…