TS EAMCET · Maths · Permutation Combination
Let \(x\) denote the number of ways of arranging \(m\) boys and \(m\) girls in a row so that no two boys sit together. If \(y\) and \(z\) give the number of ways of arranging \(m\) boys and \(m\) girls in a row and around a circular table respectively so that boys and girls sit alternately, then \(x: y: z=\)
- A \(m+1: m: m-1\)
- B \(3: 2: 1\)
- C \(m-1: m: 2\)
- D \((m+1) m: 2 m: 1\)
Answer & Solution
Correct Answer
(D) \((m+1) m: 2 m: 1\)
Step-by-step Solution
Detailed explanation
Number of ways of arranging \(m\) boys and \(m\) girls in a row such that no two boys sit together, i.e. \(x=(m+1) ! m !\) Number of ways of arranging \(m\) boys and \(m\) girls in a row such that boys and girls sit alternately, i.e. \(y=m ! \times m ! \times 2 !\) Number of…
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