TS EAMCET · Maths · Quadratic Equation
If \(a>0\) and \(b^2-4 a c=0\), then the curve \(y=a x^2+b x+c\)
- A cuts the \(x\)-axis
- B touches the \(x\)-axis and lies below it
- C lies entirely above the \(x\)-axis
- D touches the \(x\)-axis and lies above it
Answer & Solution
Correct Answer
(D) touches the \(x\)-axis and lies above it
Step-by-step Solution
Detailed explanation
Given, \(y=a x^2+b x+c\) Since, \(a>0\) and \(b^2-4 a c=0\) Therefore, given curve touch the \(x\)-axis and lies above it.
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