TS EAMCET · Maths · Straight Lines
If the line \(4 x+3 y-k=0,2 x+y+3=0\) and \(3 x+2 y+k=0\) are concurrent, then the perpendicular distance from the point of concurrency of these lines to the line \(3 x+4 y+2=0\) is
- A \(\frac{3}{5}\)
- B 1
- C \(\frac{13}{5}\)
- D 3
Answer & Solution
Correct Answer
(D) 3
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { (d) }\left|\begin{array}{ccc} 4 & 3 & -k \\ 2 & 1 & 3 \\ 3 & 2 & k \end{array}\right|=0 \\ & \Rightarrow \quad 4(k-6)-3(2 k-9)-k(4-3)=0 \\ & \Rightarrow \quad 4 k-24-6 k+27-4 k+3 k=0 \Rightarrow 3 k=3 \\ & \Rightarrow \quad k=1 \\ & \therefore \quad…
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