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TS EAMCET · Maths · Functions

Let \(x \neq 0,|x| < \frac{1}{2}\) and \(f(x)=1+2 x+4 x^2+8 x^3+\ldots\) Then, \(f^{-1}(x)=\)

  1. A \(\frac{x-1}{2 x}\)
  2. B \(\frac{x-1}{2}\)
  3. C \(\frac{x-1}{x}\)
  4. D \(1-2 x\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{x-1}{2 x}\)

Step-by-step Solution

Detailed explanation

We have, \[ f(x)=1+2 x+4 x^2+8 x^3+\ldots \text { and }|x| < \frac{1}{2} \] Let \(f(x)=y\)…