TS EAMCET · Maths · Quadratic Equation
Let \(R-(\alpha, \beta)\) be the range of \(\frac{x+3}{(x-1)(x+2)}\). Then, the sum of the intercepts of the line \(\alpha x+\beta y+1=0\) on the coordinate axis is
- A -8
- B 10
- C 8
- D -10
Answer & Solution
Correct Answer
(B) 10
Step-by-step Solution
Detailed explanation
We have, \[ f(x)=\frac{x+3}{(x-1)(x+2)} \] Let \[ y=\frac{x+3}{(x-1)(x+2)} \]…
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